In answer to the **first question**:

The zero sets of $I$ and $J$ are not enough to know whether the generators of $I$ remain a regular sequence in $\mathbb{C}[u]/J$. In particular, the zero set of $J$ is not sensitive to changes in $J$ that do not affect its radical, but these changes can be relevant to whether the generators of $I$ remain a regular sequence.

This is shown by the example Jason Starr gave in answer to [your previous question][1]. For simplicity, consider the case $m=2$, $k=1$, i.e. $\mathbb{C}[u] = \mathbb{C}[x,y]$, and let $I=(y)$, $J=(x^2,xy)$ (per Jason's example). Then the zero set of $J$ is $\{x=0\}$, and the zero set of $I$ is $\{y=0\}$. In this situation, the generator $y$ of $I$ does not remain regular in $\mathbb{C}[x,y]/J$, since it becomes a zerodivisor.

On the other hand, if $J=(x)$ (note this is the radical of the previous choice of $J$, thus it has the same zero set), then $y$ remains regular in $\mathbb{C}[x,y]/J$.

A *necessary* condition on $V(I)$ and $V(J)$ for the generators of $I$ to remain regular in $\mathbb{C}[u]/J$ (the example above shows it is not sufficient) is that 

$$\dim V(J) - \dim V(I)\cap V(J) \geq n-k.$$ 

Proof: The quotient of the noetherian ring $\mathbb{C}[u]/J$, of Krull dimension $\dim V(J)$, by a regular sequence of length $r$, has Krull dimension $\leq \dim V(J) - r$. Proof by induction on $r$: quotienting by a single regular element $a$ must reduce the dimension. If the chains of primes containing $a$ included any of maximal length, then $a$ would be contained in a minimal prime ideal, which would be an associated prime of zero, and therefore $a$ would be a zerodivisor, contrary to assumption. Thus, if $I$ is generated by a regular sequence of length $r=n-k$, the dimension of $\mathbb{C}[u]/(I+J)$ ($=\dim V(I)\cap V(J)$) must be at least $r=n-k$ lower than the dimension of $V(J)$. This is the stated claim.

Jason answered the **second question** in comments: a regular sequence in $\mathbb{C}[u]/J$ remains regular when you invert $u$, as it does in all flat extensions. See for example Proposition 1.1.2 in Winfried Bruns and Jurgen Herzog's book *Cohen-Macaulay Rings*. The argument is basically that an element being regular means multiplication by it is injective, and flat base change preserves injectivity, followed by induction on the length of the sequence.

  [1]: https://mathoverflow.net/questions/311069/on-finite-dimensional-commutative-algebras-and-regular-sequences