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Sam Nead
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Yes, all hyperbolic three-manifold fundamental groups can be generated by loxodromic elements. For, suppose that $\Gamma = \{ \gamma_i \}$ is a generating set. Take $\gamma$, a loxodromic element which is "sufficiently long" compared to the elements $\Gamma$. Then the set $\{ \gamma \} cup \{\gamma \cdot \gamma_i\}$ generates and consists only of loxodromic elements.

A more delicate argument will give loxodromic generating sets, of size two, of (say) the twist knot groups.

Sam Nead
  • 28.2k
  • 5
  • 72
  • 133