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Max Alekseyev
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Let $v_{i,j}$ be the value of $\nu_{2,j} - \nu_{1,j}$ after round $i$, with initial values $v_{0,j} = j-1$ for all $j\geq 1$. For $i\geq 1$, we have $v_{i,j} = v_{i-1,j}$ for $j\leq i$, while for $j\geq i+1$, $$v_{i,j} = v_{i-1,j} - v_{i,j-1}.$$ Correspondingly, the generating function $$F(x,y) := \sum_{i\geq 0} x^i \sum_{j\geq i+1} y^{j-i-1} v_{i,j}$$ satisfies $$(x-y-y^2)F(x,y) = x(1+y)F(x,0) - \frac{y^2(1+y)}{(1-y)^2}.$$ Plugging $y=\frac{-1+\sqrt{1+4x}}{2}$ (zero of $x-y-y^2$) in, we get $$F(x,0) = \frac1{x} \bigg(\frac{-1+\sqrt{1+4x}}{-3+\sqrt{1+4x}}\bigg)^2,$$ and correspondingly $$F(-x,0) = -\frac1{x} \bigg(\frac{1-\sqrt{1-4x}}{3-\sqrt{1-4x}}\bigg)^2,$$ matching the negated o.g.f. for A065601. Hence, $$v_{i,i} = v_{i-1,i} = (-1)^{i-1} [x^{i-1}]\ F(-x,0) = (-1)^i a(i-1).$$ QED

Max Alekseyev
  • 34.3k
  • 5
  • 74
  • 152