Skip to main content
3 of 5
added 28 characters in body
Carlo Beenakker
  • 188.1k
  • 18
  • 448
  • 651

The general pattern is as follows: $$P_{n}(x)={e}^{-x}\sum_{k=0}^{\infty}\frac{{x}^{k}}{k!}\frac{1}{\prod_{i=1}^{n} (k+2i)}=\frac{1}{x^{2n}}\biggl(\frac{e^{-x}}{2^n n! }B_n(x)+C_n(x)\biggr),$$ $$B_n(x)=\sum_{p=0}^{n-1} b_{p,n} x^{2p},\;\;C_n(x)=\sum_{p=0}^n c_{p,n} x^p,$$ $$c_{p,n}= \frac{(-1)^{p + n}(2n - p)!}{2^{n - p}p!(n - p)!}.$$ The coefficient $c_{p,n}$ is OEIS: A001498. The closed form of $b_{p,n}$ still escapes me.

Carlo Beenakker
  • 188.1k
  • 18
  • 448
  • 651