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Ismo
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Can $f: \mathbb{R}^2 \to \mathbb{R}$ be continous, open and closed?

In the last few days I've been thinking on and off about these two problems and I can get my head around them:

Let $f: \mathbb{R}^2 \to \mathbb{R}$ be a continous open map.

  1. If $f$ is surjective and $\varnothing \neq A \subseteq \mathbb{R}$ is an open set, can $f^{-1}(A)$ be bounded?

  2. Can $f$ be also closed?

The only progress I managed to make is saying that in 2. since $\mathbb{R}^2$ is both open and closed, then its image should be both open and closed, thus it must be that $f$ is surjective, since $\mathbb{R}$ is connected.

Ismo
  • 73
  • 5