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Formula for the sum $\sum_{n}^{\infty }\frac{\Omega (n)}{n^s}$ in terms of the Riemann zeta function

Is there a "closed" formula for the sum $\sum_{n}^{\infty }\frac{\Omega (n)}{n^s}$ in terms of function $\zeta(s)$ (Riemann zeta ) and its derivatives? Here $\Omega (n)$ denote the total number of prime divisors of $n$.