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Andreas Thom
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It is known that the natural map $$\iota :\bigoplus_{n \in \mathbb N} \ \mathbb Z \to Hom_{\mathbb Z} \left( \prod_{n \in \mathbb N} \mathbb Z,\mathbb Z \right)$$ is an isomorphism of abelian groups.

In particular, $\prod_{n \in \mathbb N} \mathbb Z$ cannot be a free abelian group. The crucial part of the proof appeared here. Also interesting: Noebeling showed that the abelian group of bounded sequences in $\mathbb Z$ is free as an abelian group.

Andreas Thom
  • 25.5k
  • 4
  • 82
  • 142