Skip to main content
2 of 2
added 105 characters in body
bof
  • 13.4k
  • 2
  • 43
  • 66

If $A$ is an infinite subset of $\mathbb N$, a random subset $X\subseteq\mathbb N$ will satisfy the condition $|A\cap X|=|A\cap X^c|=\aleph_0$ with probability one. Inasmuch as there are only countably many arithmetic progressions, a random subset will satisfy that condition for all of them with probability one.

Alternatively, just define $X$ to be the set of all natural numbers with an odd number of digits.

bof
  • 13.4k
  • 2
  • 43
  • 66