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Carlo Beenakker
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Both questions are answered in the Ph.D. thesis of Kalugin:

$$\alpha_{n,k}=\sum_{m=0}^k\frac{1}{m!}{{2n-1}\choose{k-m}}\sum_{q=0}^m(-1)^q (q+n)^{m+n-1}.$$

Carlo Beenakker
  • 188.1k
  • 18
  • 448
  • 651