You can evaluate $Q^0_{-3/2}(z)$ as the real part of Mathematica's LegendreQ[-3/2,z].
Carlo Beenakker
- 188.1k
- 18
- 448
- 651
You can evaluate $Q^0_{-3/2}(z)$ as the real part of Mathematica's LegendreQ[-3/2,z].