Skip to main content
3 of 3
Included the title of the linked paper
Martin Sleziak
  • 4.7k
  • 4
  • 35
  • 40

Edit: my previous answer was incorrect

No, this one you cannot do. If one had such an arrangement of circles in the solid torus inside $R^3$, and quotiented by a rotation, then by the equivariant Dehn's lemma there would be a collection of essential disks in the complement of the split link that are invariant under the symmetry.

Since the link components get permuted, no disk can have a fixed point of the cyclic action. So they are disjoint from the axis of symmetry of the rotation. Hence the components are unknotted in the solid torus, a contradiction

Ian Agol
  • 68.8k
  • 3
  • 194
  • 358