Skip to main content
4 of 4
Change for F3 the "25" to "15".
Tito Piezas III
  • 12.6k
  • 1
  • 39
  • 89

Stupid of me. As O. Gorodetsky mentions, these are classical: $$F_1=(91\zeta(3)-2\pi^3\sqrt{3})/432$$ $$F_2=(28\zeta(3)-\pi^3)/64$$ $$F_3=(117\zeta(3)-2\pi^3\sqrt{3})/243$$

In addition, note that there are almost identical cfracs for the same linear combinations where the $-$ sign is replaced by a $+$ sign: replace in $F_1$ the $312$ by $600$, in $F_2$ the $40$ by $104$, and in $F_3$ the $15$ by $51$.

Added: we have $F_4=(7/16)\zeta(3)=0.525899...$. This is due to Y. Yang and is referred to in my arXiv paper mentioned in the post.

Henri Cohen
  • 13.1k
  • 1
  • 34
  • 62