Skip to main content
4 of 4
full reference incl. doi link
David Roberts
  • 35.5k
  • 11
  • 124
  • 349

A version of OP's claim (with an additional hypothesis) is mentioned in a footnote on the first page of

where he says that M. Raynaud proved the following:

If $V$ is an algebraic variety, $f: V\to V$ has finite fibers, and is an immersion on a dense open subset of $V$, then $f$ is an isomorphism.