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Gerald Edgar
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What you easily get for any integer k >= 2 is the sum of 1/n^k over all nonzero integers n, both positive and negative. When k is even, we can use this to evaluate zeta(k). When k is odd, we get the (correct, but uninteresting) result 0.

Gerald Edgar
  • 41.1k
  • 5
  • 125
  • 219