Given two immersions $f_i: M_i^m\to N_i^n $, $i=0,1$ we can always construct an immersion $f_0\# f_1 : M_0\#M_1\to N_0\#N_1$ restricting to $f_i$ over the image of the punctured $M_i$ in the connected sum $M_i\setminus \operatorname{int}\mathbb D^m\hookrightarrow M_0\#M_1$. Indeed the connected sum operation accounts to embedding two disks, removing their interior and gluing the two manifolds along their new spherical boundary component. On the other hand since $f_i$ are immersions locally they are represented by the inclusion $\mathbb D^m\to \mathbb D^m\times\{0\}\subset \mathbb D^n$; by using the disks provided by these charts we see that the $f_i$s match on (neighbourhoods of) the boundary to give $f_0\#f_1$.
Returning to your question, given $f:M^{m}\to \mathbb R^{2m}$, consider an immersion $g:\mathbb S^m\to \mathbb S^{2m}$ with a single self intersection at points $p_0, p_1\in \mathbb S^m$ (this can be constructed by hand) and take the connected sum $f\# g: M\#\mathbb S^m\to \mathbb R^{2m}\#\mathbb S^{2m}$ (of course the disks must be disjoint from ${p_0, p_1}$).