It is well-known that if $O$ is an orthogonal map, then $\Delta u(Ox) = \Delta u$ where $\Delta$ is the Laplacian.

Now, let $A$ be a constant matrix, then we define the weighted Laplacian

$$\Delta_A = \langle \nabla, A \nabla \rangle.$$

I wonder: Does there exist a function $\varphi$ such that $Gf(x):=e^{\varphi(x)} f(Ox)$ satisfies

$$\Delta_A Gf(x) = G(\Delta_A f)(x)?$$