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Tali
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A self homeomorphism of the figure eight knot complement (not)

I was recently looking at the figure eight knot complement $M$, as a once punctured torus bundle over the surface with monodromy $ A=\begin{pmatrix} 2 & 1 \\ 1 & 1 \end{pmatrix} $ and its sister with monodromy $-A$.

I'm confused about the following: Suppose I take this bundle, with peripheral subgroup: $\lambda$ the boundary of the torus, and $\mu$ the meridian, which is vertical in my bundle picture. Now suppose I twist the top of the bundle in my picture by a full twist of $2\pi$ before gluing. I can't seem to reconcile the following three ``facts":

  1. Since I didn't actually change the monodromy I clearly get a self-homeomorphism of $M$.
  2. This homeomorphism takes $\lambda$ to itself and $\mu$ to $\mu+\lambda$.
  3. Such a homeomorphism doesn't exist by the ``knots are determined by their complements" by Gordon–Luecke.

So then, which one is wrong? Any help appreciated!

Tali
  • 111
  • 4