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Fixed another typo.
Tom Mrowka
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There are several different issues happening here. The space of $C^\infty$ is not a Banach space because the topology is generated by a countable family of semi-norms not by one norm. You might try to think about why you can’t generate the topology by some magical norm. OK so why do we care about $C^\infty$ anyway. The point is applying Sard Smale. This theorem (like Sard’s Thm) requires more regularity as the formal dimension ( index) goes up so of you want one perturbation to rule all modulo spaces no matter the index you need it to be smooth. How do you marry these two issues. The idea is to find Banach spaces \emph{contained} in $C^\infty$. The trick (which I recall appears first in Floer’s paper “The unregularized gradient flow of the symplectic action”. Perhaps he mentions that he learned the idea from Taubes. What you do is pick a rapidly decreasing sequence $\epsilon_k$ and take the norm $$\sum_k \epsilon_k \|\cdot\|_{C^k}. $$ Floer shows in that paper that for suitable sequences there are plenty (enough to get transversality) of perturbations with this norm finite but this is not all of $C^\infty$ . Thus there are Banach space of perturbations contained the smooth perturbations. We can now apply Sard Smale to a countable family of moduli space problems to get still a dense set of perturbations that are regular for all of these.

Tom Mrowka
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