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Francesco Polizzi
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The answer is yes.

In fact, there is the following result, see Banica-Stanasila, Algebraic methods in the global theory of Complex Spaces, Theorem 2.12 p. 180.

Theorem. Let $f \colon X \to Y$ be a morphism of complex spaces and let $\mathscr{F}$ be a coherent analytic sheaf on $X$, which is flat with respect to $f$. Then the restriction of $f$ to supp($\mathscr{F}$) is an open map.

In particular, every flat morphism is open.

Francesco Polizzi
  • 66.3k
  • 5
  • 180
  • 283