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Base change of cohomology when the cohomology is a torsion

Let $(R,m,k)$ be a discrete valuation ring, where $k=R/m$. Let $X\rightarrow \mathrm{Spec}R$ be a projective, integral and flat $R$-scheme. Let $\mathscr F$ be a coherent sheaf such that $H^i(X,\mathscr F)$ is a torsion for $i>0$, i.e. the $i$-th cohomology of $\mathscr F$ on the generic fiber vanishes. Then $H^i(X,\mathscr F)$ is actually a $k$-vector space. In this case, can we say anything about the following canonical map? $$H^i(X,\mathscr F)=H^i(X,\mathscr F)\otimes k\rightarrow H^i(X_k,\mathscr F_k)$$ I notice that if we let $\mathscr I$ be the ideal sheaf of $X_k$, and assume $\mathscr F$ is locally free, then we have the exact sequence $$0\rightarrow \mathscr F\otimes \mathscr I\rightarrow \mathscr F\rightarrow \mathscr F|_{X_k}\rightarrow 0,$$ Applying cohomology, we get $$\cdots\rightarrow H^{i}(X,\mathscr F\otimes\mathscr I)\rightarrow H^i(X,\mathscr F)\rightarrow H^i(X,\mathscr F|_{X_k})\rightarrow H^{i+1}(X,\mathscr F\otimes \mathscr I)\rightarrow\cdots$$ But I am not sure is there any thing interesting about $H^{i}(X,\mathscr F\otimes\mathscr I)$ in this case. Any help is appreciated.