Return to Revisions

The g.f. of these numbers (see the link) is $\sum_{n=0}^\infty S_nx^n=\frac{1-x-\sqrt{1-6x+x^2}}{2x}$. Thus radius of convergence is the same of the radical, that is the modulus of the smaller root of $1-6x+x^2$, which is $3-\sqrt{8}=\lim_{n\to\infty}\frac{S_{n-1}}{S_n}$.