*(I wanted to comment on Ira Gessel's answer, but can't - therefore as a standalone answer)*

Have a look at the excellent and comprehensive article [Eulerian Polynomials: from Euler's Time to the Present][1] from Dominique Foata. 

In it you can find the explicit formula (page 12, (2.8))
$$\sum_{i=1}^{m}{i^nt^i}=\sum_{l=1}^{n}{(-1)^{n+l}{{n}\choose{l}}\frac{t^{m+1}A_{n-l}(t)}{(t-1)^{n-l+1}}}+(-1)^n\frac{t(t^m-1)}{(t-1)^{n+1}}A_{n}(t)$$
which is in essence what Ira Gessel has described already.

  [1]: http://irma.math.unistra.fr/~foata/paper/pub117EulerUlam.pdf