This is (quite obviously) inspired by [this question.][1] Let $C_i$ be symmetric positive definite matrices. Then is it true that there is exactly one symmetric positive definite $X$ such that 
$F(X) = X^n - \sum_{i=0}^n C_i \circ X^i = 0$, where $\circ$ denotes the Schur (component-wise) product (and exponentiation is with respect to that same product) Notice that unlike in the inspiring question, the Schur product is commutative.


  [1]: https://mathoverflow.net/questions/104645/descartes-rule-of-signs-for-noncommutative-polynomia