Here is a (probably non-optimal) statement that may apply in your situation. In your situation with curves, the hypothesis says that you need $X$ and $Y$ to be Gorenstein.

**Claim.** *Let $X$ and $Y$ be noetherian schemes satisfying $G_1$ and $S_2$. If $f\colon X \to Y$ is a finite surjective morphism and $\mathscr{F}$ is a coherent reflexive sheaf on $X$, then $f_*\mathscr{F}$ is a coherent reflexive sheaf on $Y$.*

*Proof.* On noetherian schemes satisfying $G_1$ and $S_2$, reflexivity is equivalent to being $S_2$ (in Hartshorne's sense) [[Hartshorne 1994][1], Thm. 1.9]. The claim then follows since the $S_r$ property is preserved under pushforward by finite surjective morphisms by [[EGAIV$_2$][2], Prop. 5.7.9]. $\blacksquare$

I wanted to prove a statement for non-finite morphisms as well, and for integral schemes, you can say a bit more:

**Claim.** *Let $X$ and $Y$ be integral noetherian schemes satisfying $G_1$ and $S_2$. If $f\colon X \to Y$ is a proper dominant morphism with all fibers of the same dimension. If $\mathscr{F}$ is a coherent reflexive sheaf on $X$, then $f_*\mathscr{F}$ is a coherent reflexive sheaf on $Y$.*

*Proof.* The fact that $f_*\mathscr{F}$ is coherent and normal follows from the proof of [[Hartshorne 1980][3], Cor. 1.7]. By [[Hartshorne 1994][1], Rem. 1.11], to show $f_*\mathscr{F}$ is reflexive, it therefore suffices to show that it satisfies $S_1$. But being $S_1$ is equivalent to torsion-freeness for integral noetherian schemes [[Hartshorne 1994][1], Lem. 1.5], hence the claim follows by the fact that torsion-freeness is preserved under pushforwards by dominant morphisms. $\blacksquare$

**Edit.** Added the hypothesis that $f$ is surjective in the first claim.

  [1]: https://doi.org/10.1007/BF00960866
  [2]: https://doi.org/10.1007/bf02684322
  [3]: https://doi.org/10.1007/BF01467074