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Francesco Polizzi
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This is a variation of Angelo's first example. Consider a surface without rational curves and blow-up a finite number of disjoint points. If $E$ is one of the exceptional divisors and $f \colon E \to X$ is the inclusion in the blow-up, since

$H^0(E, N_{E|X})=H^1(E, N_{E|X})=0$,

we obtain $H^1(E, f^*T_X)=H^1(E, T_E)=0$, so $X$ is convex. On the other hand, $X$ is not homogeneous, since its automorphism group does not act transitively.

Francesco Polizzi
  • 66.3k
  • 5
  • 180
  • 283