I was reading a paper (the 2015 paper by A. Falkowski and L. Slominski **Stochastic Differential Equation with Constraints Driven by Processes with Bounded $p-$variation**, page 353, proof of the Lemma 3.1) for my master degree thesis.


The framework is the following: we fix 
$$
f:\Bbb R^d\to\Bbb R^d
$$
continous and such that satisfies the linear growth condition
$$
|f(x)|\le L(1+|x|),\;\;\;x\in\Bbb R^d
$$
and if $1<p\le2$ take
$$
g:\Bbb R^d\to\mathcal M_d(\Bbb R)
$$
$\alpha$-Holder continous function, where $p-1<\alpha\le1$ i.e.
$$
||g(x)-g(y)||\le C_{\alpha}|x-y|^{\alpha},\;\;x,y\in\Bbb R^d
$$
where $||A||:=\sup\{|Ax|\;:\;|x|=1\}$ is the usual matrix norm.



Fix then $a:\Bbb R_{\ge0}\to\Bbb R$ and $z:\Bbb R_{\ge0}\to\Bbb R^d$ right continous functions which admit finite left limit (RCFLF for short) such that
\begin{align*}
V_1(a)_{[0,T]}&:=\sup_{\pi[0,T]}\sum_{j=1}^n|a_{t_j}-a_{t_{j-1}}|<+\infty\\
V_p(z)_{[0,T]}&:=\sup_{\pi[0,T]}\left[\sum_{j=1}^n|z_{t_j}-z_{t_{j-1}}|^p\right]^{1/p}<+\infty\\
\end{align*}
where obviously $\pi[0,T]$ denotes the generic subdivision of the closed interval $[0,T]$.


Fix then $l:\Bbb R_{\ge0}\to\Bbb R^d$ another RCFLF function and consider the following integral equation
$$
x_t=x_0+\int_0^tf(x_{s-})\,da_s+\int_0^tg(x_s)\,dz_s+k_t
$$
whose unknown are the RCLFL functions $x,k:\Bbb R_{\ge0}\to\Bbb R^d$, with the constraint given by $x_0\ge l_0$ (inequality taken componentwise); both integral are Riemann-Stieltjes ones.


Now the Lemma of the paper I refer to, says what follows: suppose there exists $b>0$ such that
$$
\max\left[V_1(a)_{[0,T]},\;V_p(z)_{[0,T]},\;\sup_{t\le T}|l_t|\right]\le b
$$
then there exists $\bar C$ depending ONLY on $d, p, \alpha, L, g(0), x_0, b$ such that, if $(x,k)$ is a solution of the integral equation above, then
$$
\bar V_p(x)_{[0,T]}:=|x_0|+V_p(x)_{[0,T]} \le\bar C\;.
$$



I will skip all the detail of the proof, going directly to the core of the problem (otherwise the post would be the longest ever!).

I am able to prove the following inequality:
\begin{align*}
\bar V_p(x)_{[0,t]}
&\le (d+1)\left[|x_0|+LV_1(a)_{[0,t]}(1+V_p(x)_{[0,t]})+DV_p(z)_{[0,t]}(1+V_p(x)_{[0,t]})\right]+db\\
&= (d+1)\left[|x_0|+(LV_1(a)_{[0,t]}+DV_p(z)_{[0,t]})(1+V_p(x)_{[0,t]})\right]+db
\end{align*}
where $D$ is another absolute constant. Here $t\le T$.



Starting from here, we define
$$
t_1:=\inf\left\{t>0\;:\;LV_1(a)_{[0,t]}>\frac1{4(d+1)}\;\;\mbox{or}\;\;DV_p(z)_{[0,t]}>\frac1{4(d+1)}\right\}\wedge T
$$
from which immediately
$$
\bar V_p(x)_{[0,t_1[}\le(d+1)|x_0|+\frac12(1+V_p(x)_{[0,t_1[})+db
$$
and thus
$$
\bar V_p(x)_{[0,t_1[}\le2(d+1)|x_0|+1+2db\;\;.
$$
Next we accept that
$$
|\Delta x_{t_1}|=|x_{t_1}-x_{t_1-}|\le(L(1+|x_{t_1-}|)+C_{\alpha}|x_{t_1}|^{\alpha}+||g(0)||+2)b.
$$


Then the authors write there exists then $C_1,C_2>0$ depending only on $d, p, \alpha, L, g(0), b$, such that
$$
\bar V_p(x)_{[0,t_1]}\le C_1+C_2|x_0|.
$$
WHY?! I know that $\bar V_p(x)_{[0,t_1]}\le\bar V_p(x)_{[0,t_1[}+|\Delta x_{t_1}|$ but controlling $\Delta x_{t_1}$, terms depending on $x$ appear!!



Then they set
$$
t_k:=\inf\left\{t>t_{k-1}\;:\;LV_1(a)_{[t_{k-1},t_k]}>\frac1{4(d+1)}\;\;\mbox{or}\;\;DV_p(z)_{[t_{k-1},t_k]}>\frac1{4(d+1)}\right\}\wedge T
$$
thus for the same constants
$$
V_p(x)_{[t_{k-1},t_k]}\le C_1+C_2|x_{t_{k-1}}|\le C_1+C_2\bar V_p(x)_{[0,t_{k-1}]}
$$
Set now $m:=\sup\{k\;:\;t_k\le T\}$ and accept that $m$ is finite and absolute (in the sense it doesn't depend on $(x,k)$ but only on the constants already written).

How can I reach the conclusion from here? I am really confused: how can I get rid of the terms depending on $x$ in order to get my absolute estimate?