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Fedor Petrov
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$H_i$ lies on the ray $IA_i$ and $IH_i\cdot IH_i=2r^2$ (where $r=IB_i$), so $H_i$ is the image of $A_i$ under inversion with respect to center $I$ and radius $\sqrt{2}r$. Thus the result.

Fedor Petrov
  • 108.9k
  • 9
  • 264
  • 459