Skip to main content
4 of 4
\mathfrak c for cardinality of continuum; feel free to revert my edit if - for some reason - you don't wont this notation
Martin Sleziak
  • 4.7k
  • 4
  • 35
  • 40

Possible cardinalities of the remainders of compactifications of $\Bbb R$

With the usual topology on $\Bbb R$, a compactification $\mathrm{id}_{\Bbb R}:\Bbb R\to v\Bbb R$ can have a remainder $v\Bbb R \setminus \Bbb R$ of cardinality $1,2, 2^{\aleph_0}=\mathfrak c,$ or $2^{\mathfrak c}.$ The only possibilities less than $\mathfrak c$ are $1,2.$

Suppose $\mathfrak c^+<2^{\mathfrak c}.$ What possible cardinals between $\mathfrak c$ and $2^{\mathfrak c}$ can be the cardinals of such remainders?

Is there perhaps a Forcing argument that can answer or partly answer this?