Skip to main content
1 of 4
Carlo Beenakker
  • 188.2k
  • 18
  • 448
  • 651

Upon Fourier transformation the convolution becomes a product, $${\cal F}[\mu_{C}*f](k) = \exp\left(-\tfrac{1}{2}\sum_{n,m}k_n C_{nm} k_m\right){\cal F}[f](k).$$ Inverse Fourier transformation, with $k_n=i\partial/\partial x_n$, then gives Equation (1).

Carlo Beenakker
  • 188.2k
  • 18
  • 448
  • 651