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Mark Lewko
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David Speyer has given a very short proof of an upper bound for $M(n)$ in the comments. There is a similarly short argument that provides a lower bound on $M(n)$ which I believe is due to Gelfond and Schnirelmann, which goes as follows:

Let $P_n(x)$ denote a degree $n-1$ polynomial with integer coefficients. Then clearly the product $M(n) \int_{0}^{1} P_n(x) dx$ is an integer. Now consider $P(x) = x^{\frac{n-1}{2}}(1-x)^{\frac{n-1}{2}}$. For $x \in [0,1]$ we have that $P_n(x) < 2^{-(n+1)}$ since the maximum of $x(1-x)$ occurs at $x=1/2$. Thus $1 \leq M(n) \int_{0}^{1} P_n(x) dx < 2^{-(n-1)}$. Rearranging things we have that $M(n) > 2^{n-1}.$

Mark Lewko
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