It is well known that the automorphism group of exceptional Jordan Algebra $\mathcal{h}_{3}(\mathbb{O})$ is the exceptional Lie group $F_{4}$. I am trying to understand the automorphism group of the Jordan Algebra of Hermitian matrices $h_{3}(\mathbb{F})$, $\mathbb{F} = \mathbb{R}$, $\mathbb{C}$, $\mathbb{H}$. My suspicion is that at least the connected components are $SO(3)$, $SU(3)$ and $Sp(3)$, respectively. My calculations, using the matrix model of projective spaces, result in

$$RP^{2} \simeq G_{\mathbb{R}} / SO(2)$$ $$CP^{2} \simeq G_{\mathbb{C}} / SU(2)$$ $$HP^{2} \simeq G_{\mathbb{H}} / Sp(2)$$

where $G_{\mathbb{F}}$ are the desired groups, based on theorem 14.99 of Spinors and Calibration (F. Harvey). Of course, the above candidates lies in the desired groups by an action of the form $g(A) = gA\overline{g}^{t}$. I am trying to compare with: $$ RP^{2} \simeq O(3) / O(2) \times Z_{2}$$ $$CP^{2} \simeq U(3) / U(2) \times U(1)$$ $$HP^{2} \simeq Sp(3) / Sp(2) \times Sp(1)$$ References are welcome.