In a finite abelian group, I think we have the relation
f*g = sum over pairs (x,y) in the group of ([y]*([x].f)).([x]*g)
Here [x] denotes the indicator function that takes the value 1 at x and zero elsewhere. On the trivial group this says f*g = f.g, so I don't think it reduces to 0 = 0. The relation can be deduced from the fact that ([u]*h)(v) = h(v-u) for all h, u, and v, and that summing the terms over just y gives f(x).([x]*g) = f(x).g(blank - x), and the definition of convolution.