Fourier transform of $f(x)=e^{-tx^2}$ is $\hat{f}(\xi)=ce^{-\xi^2/(4t)}$.
Multiplication of $f$ by a polynomial results in applying
a differential operator with constant coefficients to $\hat{f}$, and for our $\hat{f}$ this is equivalent to multiplication on some polynomial. These polynomials play no
role in convergence (unless they are both zero), since
the expression under the exponent in the product $f(x)\hat{f}(\xi)e^{2|x\xi|}$ is
$$-tx^2+2|x\xi|-\xi^2/(4t).$$
Since this quadratic expression is sometimes positive in
the first quadrant, the integral diverges, unless $P=0$.