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Robert Israel
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Using a tabu search procedure, I have found a solution for $|P|=17$, namely ${1, 11, 18, 25, 31, 32, 33, 36, 44, 51, 58, 65, 69, 70, 77, 84, 91}$. I don't know if this is optimum.

Robert Israel
  • 54.2k
  • 1
  • 76
  • 152