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Closed a parenthesis.
Joseph O'Rourke
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Ther are not sedenions because sedenions are not associative: https://en.wikipedia.org/wiki/Sedenion

I doubt they have a name but this algebra is well understood. The hyperbolic quaternions is just $M_2({\mathbb R})$. You take a tensor product of them with usual quaternions ${\mathbb H}$. As a result you get $M_2({\mathbb H})$ that deserves no special name.

Bugs Bunny
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