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Tito Piezas III
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(This summarizes the accepted answer of Somos, and uses just the j-function and Dedekind eta function.)

Given the j-function $j(\tau)$,

$$j(\tau) = 1728J(\tau)$$

implemented in Mathematica as j(t) = 1728KleinInvariantJ[t], then Klein's septic resolvent reduces to the elegant formula,

$$y\Big(y^3-\frac{8}{\alpha^3}\sqrt{-7}\Big)\Big(y^3-\sqrt{-7}\Big)=\sqrt[3]{j(\tau)}$$

where the seven roots are,

$$y_k = \frac{P_1(k)+\alpha P_2(k)}{\eta^2(\tau)}\\ \alpha=\frac{-1+\sqrt{-7}}2$$

with $P_1(k)$ and $P_2(k)$ for $k=1,2\dots7$ as defined by Klein (and Somos).

Tito Piezas III
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