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Skeeve
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I think the answer is no.

First of all consider a related question: is the standard definition of approximate continuity of $g\colon \mathbb R \to \mathbb R$ equivalent to the following one

$$ \lim_{r \to 0} \rlap{-}\!\!\int_{B_r(x)} \min \left\{|g(y)-g(x)|,1 \right\} dy = 0. $$

This definition is in fact strictly weaker. Consider for instance the function $g(x) = \sum_{n=1}^\infty b_n \chi_{[-r_n, -r_n + a_n]}$, where $r_n = 3^{-n}$, $a_n = \frac12 4^{-n}$, $b_n = 2^n$ and $x=0$.

Then for $r=r_n$

$$ \rlap{-}\!\!\int_{B_r(x)} \min \left\{|g(y)-g(x)|,1 \right\} dy = \frac{1}{2 r_n}\sum_{k=n}^\infty a_k = \frac13 \left(\frac34\right)^{n} \to 0 $$

while

$$ \rlap{-}\!\!\int_{B_r(x)} |g(y)-g(x)| \, dy = \frac{1}{2 r_n}\sum_{k=n}^\infty a_k b_k = \frac12 \left(\frac32\right)^{n} \to \infty $$

as $n\to \infty$.

For the original question one can consider $f(x) = x g(x)$. Let me know if additional details are needed.

Skeeve
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