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Improved the statement of the question.
Qiaochu Yuan
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Can the image of a Schur functor always be made an irreducible representation?

For a partition $\lambda$ let $S^{\lambda}$ be the corresponding Schur functor. Is it true that for every $\lambda$ there exists an irreducible representation $V$ of a finite group $G$ such that $S^{\lambda}(V)$ is still irreducible?

This is not obvious to me even for the symmetric and exterior powers (although maybe I'm not thinking hard enough), so any partial results would be appreciated.

Qiaochu Yuan
  • 118.2k
  • 40
  • 447
  • 741