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Michael Hardy
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Independence of r.v.'s following a distribution that is the ratio between complex Gaussian and Chi-square r.v.'s

Given the following two R.V.s

$$z_1 = \frac{x_1}{|x_1|^2 + |x_2|^2 + \cdots + |x_M|^2}$$

and

$$z_2 = \frac{x_2}{|x_1|^2 + |x_2|^2 + \cdots + |x_M|^2}$$

where $x_i \sim \mathcal{CN}(0,a), \forall i$ and $a > 0$. As can be seen, the denominator follows a Chi-square distribution with $2M$ degrees of freedom as $x_i$ are i.i.d. R.V.s.

Based on these results (1) and (2) and on the observation that for $𝑀>5$ the real and imaginary parts of $z_i \forall i$ are normally distributed with mean equal to $0,$ can we say that $z_{1}$ and $z_2$ are independent?