Let $K=[0,1]$, $\mathfrak{R}$ is its usual Borel sigma field. $\mu$ is Lesbeque measure, $S= K\setminus \mathbb{Q}$. Then, for all Baire sets $E \subset \mathbb{Q}, \mu(E)=0$, while $$\text{supp}(\mu)= K \ne S$$
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