It can be written using a hypergeometric function
$${\mbox{$_{n+1}$F$_n$}\left(1,3,\ldots,3;\,\frac32,\ldots,\frac32;\,{\frac{1}{4^n}}\right)}$$
I don't know if further simplification is possible.
It can be written using a hypergeometric function
$${\mbox{$_{n+1}$F$_n$}\left(1,3,\ldots,3;\,\frac32,\ldots,\frac32;\,{\frac{1}{4^n}}\right)}$$
I don't know if further simplification is possible.