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Robert Israel
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It can be written using a hypergeometric function

$${\mbox{$_{n+1}$F$_n$}\left(1,3,\ldots,3;\,\frac32,\ldots,\frac32;\,{\frac{1}{4^n}}\right)}$$

I don't know if further simplification is possible.

Robert Israel
  • 54.2k
  • 1
  • 76
  • 152