I finally found the maximal parabolic subgroups of this geometry. Let us first denote the types of the elements with 0,1 and 2 when reading the diagram from left to right, and let us denote with $G_0$, $G_1$ and $G_2$ the stabilizer of an element of type 0, 1 and 2 respectively. Then we have:

$$
G_0 = G_2(4),\quad G_1 = 2^{2+8}:(A_5 \times S_3),\quad G_2 = 2^{4+6} : 3 A_6
$$
which are all maximal subgroups of $Sz$, and the Borel is $$B = 2^{12}.3^2$$
Historically, I read that this geometry was built using polar spaces (see Francis Buekenhout, _Diagrams for geometries and groups_, Journal of Combinatorial Theory A, 27, 121-151, 1979 doi:[10.1016/0097-3165(79)90041-4](https://doi.org/10.1016/0097-3165%2879%2990041-4)). However, I have not studied yet how to build it geometrically.