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Sasha
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A morphism $F \to E$ can be thought of as a representation of the quiver $$ A_2 = \{ \bullet \to \bullet \} $$ in the category $Coh(X)$. The category $Rep(A_2,Coh(X))$ is abelian, so what you need is $Ext^1$ in this category. If $S_1$ and $S_2$ denote the simple modules of the first and the second vertices of the quiver, there is an exact sequence $$ 0 \to E \otimes S_2 \to C \to F \otimes S_1 \to 0, $$ where $C = \{F \to E\}$. Using the fact that $Ext^\bullet(S_i,S_i) = \Bbbk$, $Ext^\bullet(S_1,S_2) = \Bbbk[-1]$, $Ext^\bullet(S_2,S_1) = 0$, one gets a long exact sequence $$ 0 \to Hom(C,C) \to Hom(E,E) \oplus Hom(F,F) \to Hom(F,E) \to Ext^1(C,C) \to Ext^1(E,E) \oplus Ext^1(F,F) \to Ext^1(F,E) \to \dots $$ And the space $Ext^1(C,C)$ in its middle is the tangent space to deformations.

Sasha
  • 39.3k
  • 2
  • 54
  • 104