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Igor Rivin
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Combinatorial proof of identity

The following admits of many (easy) proofs, but I am seeing no purely "bijective" argument:

$$ \sum_{j=n}^N \binom{j}{n} = \binom{N+1}{n+1}. $$

Any ideas?

Igor Rivin
  • 96.4k
  • 11
  • 153
  • 366