Problem 1 Given a irrational number $\alpha$ and two polynomials $P(n),Q(n)$, is it possible to get the asymptotic estimate and reasonable error term for: $$\lim_{N\to \infty}\#\{1\leq n\leq N \ | \ \exists m\in N^*, [P(n)\alpha]=Q(m)\}?$$

In the case when $Q(n)=an+b$, by Weyl method or van der curput trick it is not difficult to establish such a estimate at least for the asymptotic part, and if we know $\alpha$ is a smooth irrational number, we could even say some thing about the error term. In fact for smooth irrational number we have the following "effective uniformly distribution result".

Theorem (effective uniformly distribution) $\alpha \in \mathbb R- \mathbb Q$ is a smooth irrational number, then we have, $\forall 0<a<b<1$, $$\#\{1\leq n\leq N\ |\ \{\alpha P(n)\}\in (a,b) \}=(b-a)N+O(log^{deg(P)}(N))$$

The proof of this theorem is based on a careful look at the continual fraction expansion of $\alpha$.

In the case $P(n)=n$ and $Q(n) $ is a arbitrarily minimal integer polynomial (the highest order coefficient is 1) this problem is also not very difficult, in this case we could establish the following asymptotic expansion,

$$\lim_{N\to \infty}\#\{1\leq n\leq N\ |\ \exists m\in \mathbb N^*,\{n\alpha \}=Q(m) \}=N^{\frac{1}{deg(Q)}}$$

Although it seems not very easy to get a reasonable order of error term.

Although the general situation may be complicated, the typical situation I wondering to get something is the case $Q(n)=n^k+1$, and $P(n)$ is a arbitrary integer polynomial, I conjecture the following asymptotic is true.

Problem 2 $\alpha$ is a irrational number, $P(n)$ is a integer polynomial, could the following asymptotic formula be true? $$\lim_{N\to \infty}\#\{1\leq n\leq N\ |\ \exists m\in \mathbb N^*,[P(n)\alpha ]=m^k+1 \}=N^{\frac{1}{k}}$$

I will appreciate for any valuable comments and advice.