Skip to main content
1 of 2
MaJ
  • 11
  • 1

With the following additional assumptions: $K$ is compact, connected and locally convex, then it is proved in https://arxiv.org/pdf/1304.4147.pdf that $K$ is convex (Theorem 1.1). In this case, $co(K)=K$ is compact.

MaJ
  • 11
  • 1