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When solution of Schrödinger is radial?

Let $S$ be a nonnegative self- adjoint operator in a complex Hilbert Space $X$. (Say $X$ consists of functions on $\mathbb R^d$, e.g., $L^2(\mathbb R^d), \dot{H}^1(\mathbb R^d)$, etc. )

We consider the abstract Cauchy problem for the Schrödinger equation (SE):

$$i\frac{\partial}{\partial t} u(x,t) + Su(x,t)=0, u(x,0)=u_0(x)$$

Formally, we may write the solution of $(SE)$ as: $$u(x,t)= e^{itS}u_0(x).$$

Question: If $u_0(x)\in X$ is radial, then can we expect $e^{itS}u_0(x)$ also a radial?

Note:
(1) I know if $S=- \Delta$, then $e^{itS}u_{0}$ is radial whenever $u_0$ is radial.
(2) Specifically, I am interested in $S=-\Delta+ \frac{a}{|x|^2}$, see here Section 1.1 for detail (with $d\geq 3, a\geq (\frac{d-2}{2})^2$).

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