Thought I recognized this. It appears in Benham, Earnest, Hsia, and Hung (1990), Theorem 1, item (3.4). Page 6.
=====Discriminant ==Genus Size== 3
[ 1, 1, 32, 0, 0, 0 ]
[ 2, 2, 9, 2, -2, 0 ]
---**----- end of spinor genus 1 --------
[ 1, 4, 9, -4, 0, 0 ]
---**----- end of spinor genus 2 --------
The loner is one of the very few spinor regular forms that are not regular. The following constitutes a proof that $\langle 1,4,9,4,0,0 \rangle$ does not lie in the same spinor genus as $\langle 1,1,32,0,0,0 \rangle:$ we have $$ x^2 + 4 y^2 + 9 z^2 + 4yz \neq 2 m^2, $$ where all prime factors $p$ of $m$ satisfy $p \equiv 1 \pmod 4.$ There are often elementary proofs of spinor exceptional integers, once they have been noticed. In this case, $$ x^2 + (2y+z)^2 \neq 2 (m-2z)(m+2z), $$ where a crucial detail is that $z$ is odd.
This is a proof because of the Corollary to Theorem 3 of Duke and Schulze-Pillot as it is not hard to prove that the first form primitively represents all such $2m^2.$