When:
$$\frac{a^2}{b+c}＋\frac{b^2}{a+c}＋\frac{c^2}{a+b}\in\mathbb Z$$ and $\{a,b,c\}$ are coprime natural numbers and $a,b,c>1$, is there a solution except $\{183,77,13\}$?
When $\frac{a^2}{b+c}＋\frac{b^2}{a+c}＋\frac{c^2}{a+b}$ is integer and $a,b,c$ are coprime natural numbers, is there a solution except (183,77,13)?
MAEA2
- 183
- 8