When:
$$\frac{a^2}{b+c}＋\frac{b^2}{a+c}＋\frac{c^2}{a+b}\in\mathbb Z$$ and $\{a,b,c\}$ are coprime natural numbers, is there a solution except $\{183,77,13\}$?
When $\frac{a^2}{b+c}＋\frac{b^2}{a+c}＋\frac{c^2}{a+b}$ is integer and $a,b,c$ are coprime natural nubbers, is there a solution except (183,77,13)?
MAEA2
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